A few days ago i posted an article about making a JSON request using $.getJSON().
jQuery & JSON – Make JSON GET request using jQuery.getJSON()
But i have made a mistake there because i didn’t realize the Cross Domain problem. So this article shows you how to resolve the Cross Domain issue in $.getJSON() by JSONP.
1. Modify the server.php as follow.
<?php
$arr1 = array ('a'=>1,'b'=>2,'c'=>3,'d'=>4,'e'=>5);
$arr2 = array ('a'=>5,'b'=>4,'c'=>3,'d'=>2,'e'=>1);
if ($_GET['param1'] == 'ykyuen' && $_GET['param2'] == 'eureka') {
// Instead of printing the json object directy, we wrap it with the request
// callback name which is jsonp in this example
print $_GET['jsonp'].'('.json_encode($arr1).')';
} else {
print $_GET['jsonp'].'('.json_encode($arr2).')';
}
?>
2. Add the append the callback name in the request URL in the json-get.php
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js"></script>
</head>
<body>
<script>
// Append "?jsonp=?" to the request URL
$.getJSON('http://<other-domain>/server.php?jsonp=?',
{
param1: "ykyuen",
param2: "eureka"
},
success
);
function success(data) {
$.each(data, function(key, val) {
$("body").append(key + " : " + val + "<br/>");
});
}
</script>
</body>
</html>
You can name the callback arbitrarily.
Done =)
Reference: StackOverflow – “invalid label” Firebug error with jQuery getJSON
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